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Chemistry 17 Online
OpenStudy (anonymous):

How many moles are present in 16.9 g of Al2O3? 0.166 mol 0.17 mol 0.169 mol

OpenStudy (anonymous):

0.166 mol

OpenStudy (midhun.madhu1987):

Number of Moles = Given Mass / Molecular Mass = 16.9/102 = 0.166

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