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OpenStudy (anonymous):
How many moles are present in 16.9 g of Al2O3? 0.166 mol 0.17 mol 0.169 mol
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OpenStudy (anonymous):
0.166 mol
OpenStudy (midhun.madhu1987):
Number of Moles = Given Mass / Molecular Mass = 16.9/102 = 0.166
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