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Mathematics 22 Online
OpenStudy (anonymous):

PLEASE SOMEONE HELP ME AND I WILL GIVE MEDAL AND BE SOOO GREATFUL! 1.Use the quadratic equation y=x^2+3x+9 Where does the parabola lie? A) below the x- axis B) above the x-axis C) on the x-axis D) on the y-axis 2. Use the quadratic equation y=x^2-6x+9 Calculate the discriminate to determine the number of real roots. A) one real root B) two real roots C) no real roots D) no solution to the equation

OpenStudy (midhun.madhu1987):

two real roots Here Discriminant = 0 therefore there are 2 equal and real roots

OpenStudy (mrnood):

If the x^2 term of a quadratic is +ve then the parabola is u shaped (and has a minimum point) If the x^2 is -ve then it is inverted u shaped and has a maximum point

OpenStudy (solomonzelman):

By `quadratic equation` do you mean `quadratic formula` ?

OpenStudy (lochana):

1. B, 2.A

OpenStudy (mrnood):

the max or min Y value is given by m = c-(b^2/4a) Use these to find if the curve is above or below the x axis

OpenStudy (mrnood):

@SolomonZelman No - there is a quadratic EQUATION in the question

OpenStudy (anonymous):

Yeah it's quadratic equation. And thank you everyone for helping!

OpenStudy (mrnood):

For no 2 the discriminant is given by b^2-4ac If this is positive there are 2 real roots If 0 then 1 real root If -ve then 2 complex roots

OpenStudy (anonymous):

Wait so which one is it @MrNood

OpenStudy (mrnood):

so calculate the discriminant from the formula I gave you. Also please be careful of answers given here - I have seen many incorrect answers given. You should check before entering any into a test

OpenStudy (anonymous):

Is 1 B and 2 A?

OpenStudy (princeharryyy):

1.B and 2.B D=0 in case of 2nd question implying 2 real equal roots....

OpenStudy (mrnood):

Those are the answers given by other users - did you check them?

OpenStudy (anonymous):

No xc

OpenStudy (mrnood):

And now you have a conflict of answers from other users. I gave you the formulae needed for both questions......

OpenStudy (anonymous):

Lol we'll I believe that @princeharryyy is right xp

OpenStudy (mrnood):

I wouldn't

OpenStudy (anonymous):

How come

OpenStudy (anonymous):

I'm going to close this question because I need some help with some others

OpenStudy (anonymous):

But I still need help with these please? :) I wish I could give you guys like 100 medals hahaha

OpenStudy (here_to_help15):

Didn't even call me : P

OpenStudy (anonymous):

Sorry hahah you seem to be busy lately :p

OpenStudy (here_to_help15):

yeah thats true well i am not that much now : P

OpenStudy (anonymous):

Lol we'll can you help me then :)

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