Question

I don't know how to answer this non-elementary rate problem (in attached photo)

Answer 1

For each reactant, use two of the trials (where only the substance under study is changing and the other's concentration remains fixed) to determine the order (exponent) by observing how the rate changes when it's concentration is changed.

Answer 2

Ok so the two trials where the concentration is fixed would be number one and two since the H2 is stable right?

Answer 3

then i would solve for m and n ?

Answer 4

From trial 1 and 2, you can determine the order (exponent) of NO only.

Answer 5

Ok and then to find the exponent of H2 I would use trials 4 and 5?

Answer 6

yep, exactly!

Answer 7

After you find those, you can use any trial to find \(k\).

Answer 8

Thanks! Also, I got 4=2^m. I was wondering how I would isolate the m?

Answer 9

you dont need to do that. Just look at how much the rate changes when you change the concentration.

If you wanted to you could take the logarithm (or natural log)

\(ln(4)=ln(2)^m\)

\(ln(4)=m*ln(2)\)

Answer 10

ok thanks!

Answer 11

no problem! by the way, the bottom part of what i wrote doesnt apply to the question. The exponents are gonna be integers.