GCf of the rational epression.
The first thing that you will need to do is simplify your expression by factoring your trinomial. The GCF will be the largest factor that both the numerator and the denominator have in common.
hmmm can you factor the denominator?
can you help me with that please?
hmm have you done factoring of quadratics yet?
yea but i don't gt it right all the time.
What are the possible numbers when multiplied together give you 8?
4*2
\(\large \begin{array}{cccllll} x^2&-2x&-8\\ &\uparrow &\uparrow \\ &2-4&2\cdot -4 \end{array}\) any ideas on what it factors to?
this is kinda hard for me because i get confused if i have to put a number outside.
hmmm well... what do you think the denominator factors to?
yes
what pairs did you get?
\[(x+8)(x-8)\] i am not really sure if it is
When +8 and -8 are multiplied by each other, what is the product? If he answers is not the same as the "c" in you denominator, then there is a mistake.
*cough* hint *cough* \(\large \begin{array}{cccllll} x^2&-2x&-8\\ &\uparrow &\uparrow \\ &2-4&2\cdot -4 \end{array}\)
(2+4)(2-4)?
ahemm let's see (2+4)(2-4) => 4-8+8-16 => 4-16 => \(\bf -12 \ne x^2-2x-8\)
sorry i wasn't able to see it @jdoe0001
can you please give me the answer because i was just working on a question for an hour.
well... the issue is, you need to brush up on your quadratic factoring.... us writing it down for you so you can transcribe it over.... is not really "help"
can you please cause i have like 40 more pages to do for my homework.
\[(x+4)(x-2) \] @jdoe0001
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