Question

x/3 minus 1/x

Answer 1

\(\LARGE\color{blue}{ \frac{x}{3} \div \frac{1}{x} = \frac{x}{3} \times \frac{x}{1}=\frac{x^2}{3} }\)

Answer 2

that is not an answer choice
x-1/3-x
1/3
x^2-3/3x
or 3x2/3x

Answer 3

Did you type the problem out correctly?

Answer 4

yes

Answer 5

The goal is to get the denominators equal to the LCD 3x. Once they are, you can subtract the numerators and place that difference over the common denominator.

\[\Large \frac{x}{3} - \frac{1}{x}\]

\[\Large \frac{x}{3}{\color{red}{*\frac{x}{x}}} - \frac{1}{x}{\color{red}{*\frac{3}{3}}}\]

\[\Large \frac{x^2}{3x} - \frac{3}{3x}\]

\[\Large \frac{x^2-3}{3x}\]

Answer 6

seriously?

Answer 7

It's posted by two different people

Answer 8

im sorry wrong post