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Mathematics 22 Online
OpenStudy (anonymous):

Find the area of the shaded portion in the square assuming the central of each arc is the corresponding central point of the line and the arcs intersect at the center point of the circle

OpenStudy (anonymous):

OpenStudy (anonymous):

Area= area of sector - area of triangle

OpenStudy (anonymous):

I need help finding the area of the triangle

OpenStudy (jdoe0001):

hmmmm do we know anything else... because.. the shaded are is not really circular per se

OpenStudy (jdoe0001):

if you just need the triangle's area, made by the diagonal of the square. you can get that by just using the pythagorean theorem, or just the 45-45-90 rule then again, that's not the shaded area though

OpenStudy (anonymous):

There's a equation that I have to fill A=pi - ? There isn't much info given to me after that

OpenStudy (jdoe0001):

hmm can you post a quick screenshot of the material? I can see the picture..I just dunno what's being requested I don't think you can use \(\pi\) for the area per se though

OpenStudy (anonymous):

OpenStudy (jdoe0001):

hmmm

OpenStudy (jdoe0001):

anyhyow....hmm can you see what the area is? is really just a shape made from 4 circles in a square, notice the picture keep in mind the square has a side of 2 thus the diameter of each circle is 2 thus their radius is 1 keep in mind that the area of a circle is \(\bf 2\pi r^2\) so, first off, subtract 2 semi-circles from the square, that is 2 semi-circles = 1 full circle that'd leave the two triangular shapes area divided by 2, would give one of them and if you subtract that from a semi-circle.... that leaves you with the shaded area

OpenStudy (jdoe0001):

hmmm shoot forgot to add the picture..dohhh anyhow

OpenStudy (jdoe0001):

hmmm area of a circle is \(\bf \pi r^2\) rather =)

OpenStudy (jdoe0001):

|dw:1406935362113:dw|

OpenStudy (jdoe0001):

and then |dw:1406935530414:dw| notice that those two shapes left-over after the substraction, are the same ones as the traverse one

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