Question

Help me simplify this

Answer 1

\[\frac{9}{\sqrt[3]{3}}\]

Answer 2

can you show me the steps?

Answer 3

answer is

Answer 4

\[3\sqrt[3]{9}\]

Answer 5

omg my typing...

Answer 6

\[\huge = 3^{2-1/3} = 3^{6/3 -1/3}= 3^{5/3} = 3^{1 \frac{ 1 }{ 3 }} = 3\sqrt[3]{3}\]

Answer 7

how did 6/3 happen?

Answer 8

nvm

Answer 9

ahhh \[\huge = 3^{1\frac{ 2 }{ 3 }} = 3\sqrt[3]{9}\]

Answer 10

sorry so much typos

Answer 11

I typoed at the 5/3 part

because 5/3 = 1 and 2/3

Answer 12

do you get it though?

Answer 13

could you explain the last step where you converted into squareroot, I dont get it/remember how to

Answer 14

at 3 ^(1 and 2/3) ?

Answer 15

yup

Answer 16

Well here's the easier way to look at that part. I just got used to the other way.
\[\huge 3^{5/3} = \sqrt[3]{3^{5}} = \sqrt[3]{3^{3}} (\sqrt[3]{3^{2}})
= 3(\sqrt[3]{3^{2}}) =3\sqrt[3]{9} \]

Answer 17

is it confusing still?

Answer 18

the last part is cut off

Answer 19

it's just equal to \[\large 3(\sqrt[3]{9)}\]

Answer 20

or do you want to think of it as fractions?

Answer 21

\[\huge 3^{5/3} = 3^{\frac{ 3 }{ 3}}(3^{\frac{2}{3}}) = 3^{1} (3^{\frac{ 2 }{ 3 }}) \]
\[\huge = 3 (\sqrt[3]{3^{2}}) = 3(\sqrt[3]{9})\]

Answer 22

there, does this last explanation looks better?

Answer 23

oh i got it, but the nonfraction way is more comfortable

Answer 24

THANK YOU SOO MUCH :DDD

Answer 25

you're welcomed :D