The graph of f(x) = 2^x + 3 shifts 10 units to the right when it is replaced with the graph of f(x) = 2^x - k. What is the value of k
@Hero can you help me please
Actually, shifting a function of the form \(f(x) = 2^x + k\) h units to the right results in a function of the form \(f(x) = 2^{(x - h)} + k\)
So if you shifted \(f(x) = 2^x + 3\) ten units to the right, you'd end up with \(f(x) = 2^{x - 10} + 3\) Shifting \(2^x + 3\) by k units would result in a vertical shift.
@Glorenda49
I posted three functions on desmos.com: \(f\left(x\right)=2^x+3\) (original function) \(f\left(x\right)=2^{\left(x-10\right)}+3\) (shifted original function 10 units right) \(f\left(x\right)=2^x-5\) (when k = -5, it shifts function 8 units down, not right) I hope this makes sense.
I understand it
thanks :)
You're welcome
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