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Mathematics 18 Online
OpenStudy (anonymous):

Feedback.

OpenStudy (anonymous):

OpenStudy (anonymous):

Sorry @OOOPS your helping me a lot

OpenStudy (anonymous):

nope for the first one

OpenStudy (anonymous):

Okay... and the rest?

OpenStudy (anonymous):

Let's tag others. I am sorry, I am quite tired, dare not to give you what I don't think carefully. @ganeshie8

OpenStudy (anonymous):

okay thank you!

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

okay how about the rest.

OpenStudy (anonymous):

OKay thank you.

OpenStudy (anonymous):

is 22 going to be 27:8

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (phi):

There is an relation between "scaled" figures (the same shape, but one is an enlarged version of the other) this rule works for any shape. if you make all the sides 3 times bigger, the area (or surface area) goes up by the square. in other words 3^2 and the volume goes up by the cube, 3^3

OpenStudy (anonymous):

which question are we discussing

OpenStudy (phi):

For question 22, you have a *length* (the radius) that is changed from 6 to 4 the cylinders are similar, so that means that if we changed the radius, *everything* else was shrunk in the same way. now we use the rule: the surface area changes by the square of 6/4 the volume changes by the cube of 6/4

OpenStudy (phi):

you should first simplify 6/4 by dividing top and bottom by 2 to get 3/2 that is the ratio of *lengths* (e.g. the radius, or the height) the ratio of their surface areas will be (3/2)^2 or (3/2)*(3/2) the ratio of their volumes will be (3/2)^3 or (3/2)*(3/2)*(3/2)

OpenStudy (phi):

For Q23, they give you a scale factor of two similar figures as 2:5 (this applies to the length of the figure) this immediately tells you the ratio of their surface areas: (2/5)^2 and the ratio of their volumes: (2/5)^3

OpenStudy (phi):

can you answer the first question?

OpenStudy (anonymous):

I think that is is 27:8 but Im not quite sure

OpenStudy (phi):

the ratio of their volumes will be (3/2)^3 or (3/2)*(3/2)*(3/2)

OpenStudy (anonymous):

so therefore I am right!

OpenStudy (anonymous):

Because when you multiply 3*3*3 you get 27 and when you multiply 2*2*2 you get 8 I don't think that you can simplify that.

OpenStudy (phi):

if you multiply 3/2 * 3/2 * 3/2 you get 27/8 You start with: ratio of similar figures is 6/4 = 3/2 (and this is a ratio of *lengths*) now you know the ratio of their surface areas is (3/2)^2 and volumes (3/2)^3

OpenStudy (phi):

ok, that was the first question. Can you try Q23?

OpenStudy (anonymous):

yes, 23 so what you to do is do 2/5*2/5*2/5

OpenStudy (phi):

in Q23 it is asking about *area* (not volume)

OpenStudy (anonymous):

only twice*

OpenStudy (anonymous):

yeah sorry, 2/5*2/5

OpenStudy (phi):

yes 2/5 * 2/5 = (2*2)/ (5*5)

OpenStudy (anonymous):

which equals 4/25

OpenStudy (anonymous):

so it would be false?

OpenStudy (phi):

yes, it's false

OpenStudy (anonymous):

yeah! And I don't get 24

OpenStudy (phi):

scale factor 1:12 (which means lengths) example: toy train is 1 ft long, real train is 12 feet long. what is the ratio for *area* ?

OpenStudy (anonymous):

Square it

OpenStudy (phi):

yes, what do you get? you have 1/12 for lengths what is it for area ?

OpenStudy (anonymous):

It would be 1:24

OpenStudy (phi):

the ratio for areas is (1/12)*(1/12) multiply top times top and bottom times bottom 1/144 ( FYI and for volumes the ratio is 1/1728 )

OpenStudy (anonymous):

oh okay sorry

OpenStudy (phi):

1/24 is 1/12 * ½ which is not correct

OpenStudy (phi):

now that you have the ratio of surface areas we use it in an equation of ratios

OpenStudy (anonymous):

yeah I did a math error your suppose to do 12*12 not 12*2

OpenStudy (phi):

the ratio 1/144 is model's area/actual area we set that equal to the model's area/ x unknown actual area

OpenStudy (anonymous):

so would it be|dw:1406945144039:dw|

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