Express f(x) in the form a(x − h)2 + k.
f(x) = x^2 − 6x + 12

what happened..? its answer is
f(x) = {(x -3)^2 -9} + 12
=(x-3)^2 + 3

how did this happened..?

Question

Express f(x) in the form a(x − h)2 + k.
f(x) = x^2 − 6x + 12

what happened..? its answer is 
f(x) = {(x -3)^2 -9} + 12
       =(x-3)^2 + 3

how did this happened..?

lochana · Answer

f(x) = {(x -3)^2 -9} + 12
       =(x-3)^2 + 3

anonymous · Answer

thats it..? thats the final answer..? u just simplify it..?

lochana · Answer

yes, now we can say a=1, h=3, k=3

anonymous · Answer

ahhh.. tnx tnx..

lochana · Answer

u got it, right?

anonymous · Answer

yep.. i got it..

precal · Answer

we used a method called completing the square to convert from standard form to vertex form

precal · Answer

x^2 − 6x + 12
take the middle number (in this case 6)
6/2 = 3
3^2 is 9
so we are going to +9-9  because this creates a zero

precal · Answer

x^2-6x+9+12-9
(x-3)^2+12-9
(x-3)^2+3

precal · Answer

note:  (x-3)^2   when you expand it out is x^2-6x+9

precal · Answer

any other questions

anonymous · Answer

wow.. sorry.. haha.. tnx for the help.. i now understand how to do it.. tnx..

precal · Answer

any time
here are some quick things to keep in mind
always take the middle terms number 
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