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Trigonometry
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sin(B-A) is equal to ??????? when B=270 degrees and A is an acute angle.
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well sin 270-A=-cosA
?
its a way of converting to acute angles
hmm
so sin 270-A = cosA
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Kindly explain......Im slow
Well when we know one angle is 270, it is in the third quadrant
Now 270 = 3x90
because 3 is odd, the name will change from sin to cos (for even numbers, it stays as the original)
In the third quadrant, cosine is negative
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Do I need to prove? And are you using the pythagorean Identity?
|dw:1406983659137:dw|
no i am not, it is just the angle being in the third quadrant, no proving of pythagoreas is necessary
So which identity does it belong?
its not an identity, it is just conversion of an angle
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here look at this picture
|dw:1406983853670:dw|
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