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Trigonometry 17 Online
OpenStudy (anonymous):

sin(B-A) is equal to ??????? when B=270 degrees and A is an acute angle.

OpenStudy (crashonce):

well sin 270-A=-cosA

OpenStudy (anonymous):

?

OpenStudy (crashonce):

its a way of converting to acute angles

OpenStudy (dan815):

hmm

OpenStudy (crashonce):

so sin 270-A = cosA

OpenStudy (anonymous):

Kindly explain......Im slow

OpenStudy (crashonce):

Well when we know one angle is 270, it is in the third quadrant

OpenStudy (crashonce):

Now 270 = 3x90

OpenStudy (crashonce):

because 3 is odd, the name will change from sin to cos (for even numbers, it stays as the original)

OpenStudy (crashonce):

In the third quadrant, cosine is negative

OpenStudy (anonymous):

Do I need to prove? And are you using the pythagorean Identity?

OpenStudy (crashonce):

|dw:1406983659137:dw|

OpenStudy (crashonce):

no i am not, it is just the angle being in the third quadrant, no proving of pythagoreas is necessary

OpenStudy (anonymous):

So which identity does it belong?

OpenStudy (crashonce):

its not an identity, it is just conversion of an angle

OpenStudy (dan815):

here look at this picture

OpenStudy (dan815):

|dw:1406983853670:dw|

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