Question

If the endpoints of a diameter of a circle are A(2, 5) and
B (7, 2), what is the radius of the circle?

Answer 1

You would do Midpoint first and then distance formulas right?

Answer 2

@MathMan321

Answer 3

\[2r=\sqrt{(7-2)^2+(2-5)^2}\]
\[2r=\sqrt{34}\]
So the radisu is sqrt(34)/2

Answer 4

so the answer would be Sqrt(17)

Answer 5

Nope.
\[\frac{ \sqrt{34} }{ 2 }=\frac{ \sqrt{34} }{ \sqrt{4} }=\sqrt{\frac{ 34 }{ 4 }}=\sqrt\frac{ 17 }{ 2 }\]

Answer 6

So it would be sqrt(17/2)

Answer 7

why did you go from 2 to sqrt of 4

Answer 8

There is a property of square root\[\frac{ \sqrt{a} }{ \sqrt{b} }=\sqrt{\frac{ a }{ b }}\] where a>=0 and b>0

Answer 9

oh okay, so the answer wuld be sqrt17/2

Answer 10

yep

Answer 11

thanks

Answer 12

welcome :)

Answer 13

Can you help me with this one it is a true or false question
I just meed feedback.

Answer 14

@science0229

Answer 15

yeah