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Mathematics 19 Online
OpenStudy (jessiegonzales):

MEDA!!!!!! Find the value of X! Step by step please :)

OpenStudy (jessiegonzales):

OpenStudy (nincompoop):

try

OpenStudy (jessiegonzales):

@zepdrix

OpenStudy (nincompoop):

http://www.mathopenref.com/trianglemidsegment.html TRY!

OpenStudy (nincompoop):

yo, let her figure this one out

zepdrix (zepdrix):

|dw:1407010829469:dw|We have similar triangles, yes? If you call this lower piece something like ... \(\Large\rm a\) Then you can setup your relation for similar triangles:\[\Large\rm \frac{2x-6}{a}=\frac{16}{a+a}\]

zepdrix (zepdrix):

|dw:1407011019543:dw|Understand how I setup that relationship? :o There's a nice shortcut for this one actually, but I was hoping this might help you understand the concept.

OpenStudy (jessiegonzales):

okay yes im understanding!

zepdrix (zepdrix):

\[\Large\rm \frac{2x-6}{a}=\frac{16}{a+a}\] \[\Large\rm \frac{2x-6}{a}=\frac{16}{2a}\]Multiply both sides by a,\[\Large\rm 2x-6=\frac{16}{2}\]And here we can see what the relationship is telling us. The 2x-6 side is `half the length` of the 16 side. Do you understand how to solve for x form that point?

OpenStudy (jessiegonzales):

so will it be 2x-6=8

zepdrix (zepdrix):

mhm c: solve for x.

OpenStudy (jessiegonzales):

x=7

zepdrix (zepdrix):

yay good job c:

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