Question

NEED help please, how would i find the confidence interval of a cointoss of 100 times, what do i need

Answer 1

@nincompoop @vishweshshrimali5 @amilapsn can anyof u tell me how to figure thise out please

Answer 2

i have all the data just dont know what to do with
what

Answer 3

http://stattrek.com/estimation/confidence-interval.aspx I think this would be helpful to you...

Answer 4

Please start by stating specifically what your confidence interval will estimate. Are you looking to find a confidence interval for the mean of some characteristic of a population, or are you looking to find a conf. int. for some proportion of the population?

Secondly, obtain or decide upon the level of confidence desired. Do you want to find an 80% confidence interval, or a 95% one, or a 99% one? Find the corresponding z-critical value.

Although I'm signing off the 'Net now, I expect to be back on sometime tomorrow.

Answer 5

okay please answer back when u get back on @mathmale , sample proportion 100 tosses of a coin, 48.33 are heads, 99.7% 95% and 68% all 33 intervals , what else do u need to know

Answer 6

Summarizing what you have given me: n=sample size=100
Quantity (parameter) to be estimated: population proportion
Sample proportion: 48.33/100, or just 0.4833
Desired level of confidence: 95%
z-critical value for a 95% confidence interval: 1.96

The confidence interval will have the following form:\[p _{0}\pm(z-critical value)\sqrt{\frac{ p _{0}(1-p_{0)} }{ n}}\]

Answer 7

Please substitute the knowns/givens into this formula. Show your result here. Ask questions liberally if this discussion is not sufficiently clear for you.
Note: \[p _{0}\]denotes the sample proportion, which is given.

Answer 8

what is z-critical value how do i put that in the calculator

Answer 9

@mathmale

Answer 10

what kind of calculator are you using? And do you happen to have a table of standardized z scores?

Answer 11

ti-83+, and no sorry i dont

Answer 12

OK. Have you gotten much experience drawing standard normal curves?