Question

integration by parts

Answer 1

\[\int\limits_{1}^{4} \sqrt{x}\ln x dx\]

Answer 2

Any attempts?

Answer 3

yes so far

u= ln x dv= x^1/2 dx
du= 1/x dx v=2/3 x^(3/2)

\[\int\limits_{1}^{4} \sqrt{x} lnx dx= (\ln x) \frac{ 2 }{ 3 } -\int\limits \frac{ 2 }{ 3 }x ^{\frac{ 1 }{ 2 }} ]\frac{ 4 }{ 1 }\]

Answer 4

mean from 1 to 4 not a fraction

Answer 5

@iambatman

Answer 6

I chose u to be lnx I got the integral nice
Can you try that

Answer 7

Oh you have done the same. I guess you missed something there.

Answer 8

You are doing good you just forget something there

Answer 9

what did i forget?

Answer 10

I'm sorry I'm using the phone haha. I might have mistakes there because I did it quickly. Check it and see