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How do I expand 4cos(6x) in terms of sines using the double angle identity?
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Your attempt?
Hint 6x = 2(3x)
\(cos 2(x) = 1- 2sin^2 (x)\) now you have \(cos 2(3x) = 1-2sin^2(3x)\) , got me so far??
Yes.
so?? just times4 in the front both sides, you get what you want to get. \(\color {red}{4}cos (6x)= \color{red}{4}*....\) can you finish??
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Yeah. Totally. That was way simpler than I was trying to make it be.
Thank you so much.
hahahahaa
I was breaking it into cos(3x+3x) and using that identity and it was a total mess. Thank you.
ok
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