1. Draw a 30-60-90 triangle. Label all angle measures and side relationships. Using the side relationships from the figure, show that the following trigonometric identities hold true for the given angles:
tan 60=sin 60/cos 60
i know it is true, but why
\[\sin ^{2}(30)+\cos ^{2}(30)\]
ummmm im not doin tricanometry or geometry so im sorry :(
and this too i got the triangle and the sides
its alright :)
now from the graph you would know cos 60 =A/C sin 60=B/C tan 60 =B/C |dw:1407110185239:dw| now sin 60 / cos 60 = B/C *C/A=B/A=tan 60 does this make sense to u ?
nop
i made a typo on the graph :P it should be like this |dw:1407110267063:dw| ok ill do from skratch
ok u have this triangle with sides A,B,C with me so far? |dw:1407110355925:dw|
yes
so sin 60 = Contrast /hypotenuse=B/C right ?
yes
could u find cos 60 and tan 60 as well ?
i believe cos 60 = c/a?
and tan60 = a/b
well cos theta =adjacent /hypotenuse = A/C
cos 60 =A/C
and tan 60 = adjacent /Contrast
so tan 60 =B/A ok ?
oh okay, so, do you mind helping more, like what are the sides?
|dw:1407111090155:dw|
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