Question

What is the simplified form of (24y^5/15x^8)/(8y^2/4x^4)?

Answer 1

Dividing by a term is equivalent to multiplying by that term's reciprocal, if that helps

Answer 2

Yeah, I can get that part
\[\frac{ 24y ^{5} }{ 15x ^{8} }\times \frac{ 4x ^{4} }{ 8y ^{2} }\]

Answer 3

Now just cancel the exponents out, for example, the 24y^5/8y^2 is just 3y^3

Answer 4

\[\frac{ 3y ^{3} }{ 15x ^{8} }\times \frac{ 4x ^{4} }{ 3y ^{3}}\]
Like this?

Answer 5

Noooo the y term on the right got deleted after the simplification

Answer 6

\[\frac{ 3y ^{3} \times4x ^{4}}{ 15x ^{8} }\]
So like this?

Answer 7

Yep, now do the same with the x terms

Answer 8

I don't think they can cancel out

Answer 9

They can, but the bottom x term has a bigger exponent so the top x will be gone afterwards

Answer 10

\[\frac{\left(4 x^4\right) \left(24 y^5\right)}{\left(15 x^8\right) \left(8 y^2\right)}=\frac{4 y^3}{5 x^4} \]

Answer 11

Aww giving the answer away is no fun

Answer 12

So am I just subtracting the exponents?

\[\frac{ 3y ^{3}\times4x }{ 15x ^{4}}\]

Answer 13

Basically, don't forget that x by itself is still x^1

Answer 14

\[\frac{ y ^{3}\times4 }{ 5x ^{4} }\]

And then it would be robtobey's answer, right?

Answer 15

Yep looks good to me

Answer 16

See not so bad was it?

Answer 17

Thank you :)

Answer 18

Was a pleasure