Need to know how to solve a rational equation
The following equation is one that I made up so I can solve the problem I have to do on my own.
|dw:1407178562891:dw| this is the equation I made
|dw:1407178841444:dw|
I don't know why it came out like that
I would start like this: \[(x^3-8x)^{-1}=\frac{x}x+\frac8x-6\]
okay hold on let me put the other equation in that form @agreene
Where did the ^-1 outside the first parenthesis come from? @agreene
its shorthand for the division
\[\frac1x=x^{-1}\]
so the ^-1 is coming from the 1 in the first part of the equation?
yes
okay so I put my equation in that form whats next?
you there? @agreene
what do I doo next?
lol im trying to remember.. im a bit rusty on the algebra here
haha its okay
\[\frac1{x^3-8x}=1+\frac8x-6\] \[\frac1{x^3-8x}=\frac8x-5\] \[\frac1{x^3-8x}-\frac8x=-5\]
The least common denominator is (x^3-8x). Multiply throughout by (x^3-8x). You will get a fourth degree polynomial which cannot be easily solved unless you use a graphic calculator. Note that x cannot be 0 or \(\pm\sqrt{8}\) because that would make the denominator zero.
My equation was
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