Question

How would you solve 23^x=6? I think you have to take log from both sides but I don't know what to do after that.

Answer 1

What do you get when you do that?

Answer 2

xlog23=log6

Answer 3

Now try putting both sides over e, the log should cancel out, leaving (e^x)(23)=6

Answer 4

Simplify to e^x=6/23

Answer 5

That was the longer way around btw, didn't know if you knew how log/log worked

Answer 6

Log/log is just change of base formula isnt it?

Answer 7

Now take log of both sides, e will go away leaving x=log(6/23)=log6-log23

Answer 8

Should be easier to find the answer now with a calculator

Answer 9

I probably could have done that quicker still, but that's how I would have done it if I was still experimenting

Answer 10

Would the answer then be x=log(6/23)?

Answer 11

You could leave it like that too, I like the other form better imo =P

Answer 12

Awesome! Thanks, I really struggled on the whole log concept, it's pretty complicated imo