If you mix 125mL of 3M HCl and 145mL of 3M CO3-2 , what is the pH? is it 9.6?
ph = -log[H+]
So you are diluting the strong acid
I guess this is a buffer solution you will want to use Henderson–Hasselbalch equation most likely
https://www.khanacademy.org/science/chemistry/acids-and-bases/v/buffers-and-hendersen-hasselbalch This will probably explain how to perform the calculation adequately, if it doesn't I can help you with it
First thing you want to do is recalculate the concentration of each solution though taking into account that you diluted both of them by putting them together
125+145 = 270mL final volume
CO3 -2 is a strong base right?
No
It is a weak base
The CO3-2 reacts with water to form hydroxide ions, it isn't 100% ionized
CO3-2 + H2O -> HCO3- + -OH
I dont know how advanced your course is but you can either ignore the carbonate completely or you can use the Henderson–Hasselbalch equation
Thank you, that is what I did, I used the Henderson–Hasselbalch equation for the CO3 and HCO3 species
Join our real-time social learning platform and learn together with your friends!