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Chemistry 23 Online
OpenStudy (anonymous):

If you mix 125mL of 3M HCl and 145mL of 3M CO3-2 , what is the pH? is it 9.6?

OpenStudy (australopithecus):

ph = -log[H+]

OpenStudy (australopithecus):

So you are diluting the strong acid

OpenStudy (australopithecus):

I guess this is a buffer solution you will want to use Henderson–Hasselbalch equation most likely

OpenStudy (australopithecus):

https://www.khanacademy.org/science/chemistry/acids-and-bases/v/buffers-and-hendersen-hasselbalch This will probably explain how to perform the calculation adequately, if it doesn't I can help you with it

OpenStudy (australopithecus):

First thing you want to do is recalculate the concentration of each solution though taking into account that you diluted both of them by putting them together

OpenStudy (australopithecus):

125+145 = 270mL final volume

OpenStudy (anonymous):

CO3 -2 is a strong base right?

OpenStudy (australopithecus):

No

OpenStudy (australopithecus):

It is a weak base

OpenStudy (australopithecus):

The CO3-2 reacts with water to form hydroxide ions, it isn't 100% ionized

OpenStudy (australopithecus):

CO3-2 + H2O -> HCO3- + -OH

OpenStudy (australopithecus):

I dont know how advanced your course is but you can either ignore the carbonate completely or you can use the Henderson–Hasselbalch equation

OpenStudy (anonymous):

Thank you, that is what I did, I used the Henderson–Hasselbalch equation for the CO3 and HCO3 species

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