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Chemistry 17 Online
OpenStudy (anonymous):

oxidation numbers of: 2KOH + K2Cr2O7 --> 2k2CrO4 + H2O AgNO3 + KI --> AgI + KNO3 2PbS + 3O2 --> 2PbO + 2SO2

OpenStudy (anonymous):

@JoannaBlackwelder how do I do this?

OpenStudy (joannablackwelder):

Do you have a lost of the rules?

OpenStudy (joannablackwelder):

* list :)

OpenStudy (anonymous):

no I don't... I know that any one element is 0

OpenStudy (joannablackwelder):

Good! The sum of compounds adds up to the charge on the compound as well. Here is a link to a list of the rules. http://www.chemguide.co.uk/inorganic/redox/oxidnstates.html

OpenStudy (anonymous):

I'm not really sure I get it... can we do the first one @JoannaBlackwelder

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