Solve for x. 7^(x-2)=12^(x)
@dumbcow any help :))
use logs \[\ln a^n = n \ln a\]
can you explain that ? :/
its a log property you will use to solve this whenever the exponent "x" is a variable, you can take the log and bring the exponent outside of the log
oh okay, makes sense
i am a bit stuck. Can you show me ?
\[\rightarrow (x-2) \ln 7 = x \ln 12\]
would I then divide each side by ln12 to get x ?
no because there is an "x" on other side too distribute, then put "x" terms on same side factor out the "x" , then you divide
how do i do that ?
just like how i described :) do you know how to distribute?
distribute what ?
(x-2) ln7 ?
yes ... sorry got to go
xln(7)-2ln(7)
wait but what do I do next..... :((
@mathmale can you plzz continue from where dumbcow left off, he had to go ?
7^(x-2)=12^(x) became \[\rightarrow (x-2) \ln 7 = x \ln 12\] (This is correct. Any questions regarding what's happening here?)
no
Our job is to solve for x. In other words, we want to isolate x on the left side of this equation and have everything else on the right side.
okay
Please multiply out the left side of \[\ (x-2) \ln 7 = x \ln 12\]
xln(7)-21ln(7)=xln(12)
Which of these terms contain a variable and which does/do not?
Collect all with x in them on the left; collect all constants on the right.
so I need to add 21ln(7) and subtract xlm(12) from both sides
Yes, that's right. Try it.
ok so: xln(7)-xln(12)=21ln(7) But what happens next here ?
Both terms on the left have x in them. Factor out x and write the remaining factor inside parentheses. Leave the right side alone.
ok, that makes sense, but I do I factor the x ?
@mathmale
xln(7)-xln(12)=21ln(7) becomes x (ln 7 - ln 12) = 21 ln 7.
oh okay
How would you now solve for x?
do i use a calculator and solve the inside parenthesis first ?
No. Best to use a certain "rule of logs" to combine ln 7 - ln 12 into one log. Of course, if you're supposed to find the answer as a decimal fraction, then go ahead and use your calculator.
ok how would i combine, can you teach me it ?
The rule of logs that applies here is log a - log b = log (a/b). Therefore, log 7 -log 12 = ?
log(7/12)
ok I got it from there, thank youuuuuu...hhehe :)))) What are the benefits from getting the membership on os. Do you like it ?
You're welcome! I'm a retired teacher and love to continue working with students on their math through OpenStudy. I'm also a Moderator and can thus help keep OS clean and focused.
That's awesome! :) you're very kind! :)
wait, but I try to solve x and I get -16.625 and when I plug it in it doesn't seem to work
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