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Papa's Italian Restaurant has collected data about customer sauce orders. It calculated that P(marinara) = 0.74, P(pesto) = 0.62, and P(marinara or pesto) = 0.90. Determine the P(marinara and pesto). 0.12 0.46 0.16 0.22
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Let the event 'has marinara' be M and let the event 'has pesto' be P. \[P(M \cup P)=P(M)+P(P)-P(M \cap P)\ ........(1)\] Plugging in the given values of probability into (1), we get: \[0.9=0.74+0.62-P(M \cap P)\ ..........(2)\] So now you just need to solve equation (2) to find the required intersection of marinara and pesto.
So the answer is .46, I believe. That's what my original thought was but I kept second guessing myself. Am I right?
Yes, 0.46 is the solution.
thank you
You're welcome :)
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