Question

Factor.
4x^4-19x^3-5x^2

Answer 1

\[4x ^{4}-19x ^{3}-5x ^{2}\]

Answer 2

\[4x^4-19x^3-5x^2=x^2(4x^2-19x-5)\] is a good start

Answer 3

Then factor by grouping?

Answer 4

i don't know i suck at factoring
as far as i can tell factoring by grouping is the same as factoring by trial and error

Answer 5

Haha :) Well thank you very much, I think I've got it by now. I suck at factoring when it comes to anything to a degree higher than 2

Answer 6

i would set it equal to zero and solve
the answer will be
\[x^2(4x+1)(x-5)\]

Answer 7

how you factor
\[4x^2-19x-5\] using any method other than trial and error is a mystery to me
if you have a method, bless you

Answer 8

or quadratic formula but for this you will need to get the equation in (ax^2+bx+c=0) form then its easier and it would give you answers x = 0, x= -1/4 and x= 5

Answer 9

Well, from what you already did for me (sorry for saying it like that but you did) All I gotta do now is multiply A and C and find factors of B that multiply to the product of AC and add up to B

Answer 10

@satellite73 i have a question

Answer 11

??

Answer 12

@lankymonkey i don't answer questions

Answer 13

how did you get to smartscore 100

Answer 14

oh umm sorry satelite are you a robot?

Answer 15

?????????????? Private message each other ????????????

Answer 16

umm ok sry satelite

Answer 17

why was satelite acting weird? and why do moderators and admins hate me????