Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x. f(x)=(x-8)/(x+7) and g(x)=(-7x-8)/(x-1)
no one wants to do this algebra, because it is a real pain
That's not the right attitude to get a problem done now is it? @satellite73
have fun
\[f(x)=\frac{x-8}{x+7}\] \[g(x)=\frac{-7x-8}{x-1}\]
\[f\circ g(x)=f\left(\frac{-7x-8}{x-1}\right)\] \[=\frac{\frac{-7x-8}{x-1}-8}{\frac{-7x-8}{x-1}+7}\]
clear the compound fraction by multiplying top and bottom by \(x-1\) use parentheses and do the algebra carefully
when you do it there will be an orgy of cancellation the likes of which is usually unseen and you will be left with only \(x\)
Thank you for your help @satellite73 I appreciate it, have a good night.
you too good luck with this one
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