Question

how does y=(x)/(x^2+1) have origin symmetry using the algebraic method ? I inputted (-x) and (-y) and it was different from the original equation.

Answer 1

replace \(x\) by \(-x\) and you get
\[\frac{-x}{(-x)^2+1}\] is a start

Answer 2

then since \((-x)^2=x^2\) you have
\[\frac{-x}{x^2+1}\] which is in fact \(-\frac{x}{x^2+1}=-y\)

Answer 3

Omg. Thank you. So stupid of me. I really appreciate you answering my question !