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Mathematics 19 Online
OpenStudy (mathmath333):

find the remainder when 59^28 is divided by 7

OpenStudy (anonymous):

You need to look for a pattern here

OpenStudy (anonymous):

So check a few exponents and see if you can see a pattern

OpenStudy (mathmath333):

(7*8+3)^28

OpenStudy (anonymous):

Yes, this requires binomial theorem, do you know how it works?

OpenStudy (mathmath333):

i am relying on the formula(ax+1)^n/a which gives remainder as 1

OpenStudy (anonymous):

you know the cycle of 8 how it goes right?---------->8,4,2,6 and it repeats. mow 58 means take unit digit 8 from that and then raise to power 6 which gives remainder 8. divide remainder by 7------->1 is the remainder

OpenStudy (mathmath333):

the book is showing the remainder as 4

OpenStudy (anonymous):

Yeah 4 is the remainder

OpenStudy (mathmath333):

whats the trick to find remainder of 2^14/7

OpenStudy (anonymous):

yeah got it unit digit is 6 as we can see the process....now counting 6 times from tops give you 4 and dividing 4/7= 4 as remainder

OpenStudy (anonymous):

see it as 8^6-------> 4 as unit digit.

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