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OpenStudy (anonymous):
You need to look for a pattern here
OpenStudy (anonymous):
So check a few exponents and see if you can see a pattern
OpenStudy (mathmath333):
(7*8+3)^28
OpenStudy (anonymous):
Yes, this requires binomial theorem, do you know how it works?
OpenStudy (mathmath333):
i am relying on the formula(ax+1)^n/a which gives remainder as 1
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OpenStudy (anonymous):
you know the cycle of 8 how it goes right?---------->8,4,2,6 and it repeats. mow 58 means take unit digit 8 from that and then raise to power 6 which gives remainder 8. divide remainder by 7------->1 is the remainder
OpenStudy (mathmath333):
the book is showing the remainder as 4
OpenStudy (anonymous):
Yeah 4 is the remainder
OpenStudy (mathmath333):
whats the trick to find remainder of 2^14/7
OpenStudy (anonymous):
yeah got it unit digit is 6 as we can see the process....now counting 6 times from tops give you 4 and dividing 4/7= 4 as remainder
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