Question

sec theta +tan theta=p then sin theta=

Answer 1

(sec theta+tan theta)^2=p^2

(sec ^2 theta= tan ^2 theta+2 tan theta sec theta)=p^2

Answer 2

1+2 tan theta sec theta=p^2

Answer 3

1+2 sin theta/cos theta*1/cos theta=p^2

Answer 4

2 sin theta/cos^2 theta=p^2-1

Answer 5

2 sin thetA/1-sin^2 theta=p^2-1

Answer 6

2sin theta-2/sin theta=p^2-1

Answer 7

1+sin theta =p cos theta

Answer 8

then @campbell_st

Answer 9

well if you want to square it then its

\[\sec2(\theta) + \tan^2(\theta) + 2\tan(\theta)\sec(\theta) = p\]

I don't understand how you said sec^2 + tan^2 = 1

as sec^2 = tan^2 + 1so if you substitute its

tan^2 + 1 + tan^2 + 2tansec = p

Answer 10

oops

\[\sec^2(\theta) + \tan^(\theta) + 2\sec(\theta)\tan(\theta) = p\]

Answer 11

I would have used the fact that

\[\sec(\theta) + \tan(\theta) = p...so..... \frac{1}{\cos(\theta)} + \frac{\sin(\theta)}{\cos(\theta)} = p\]

then

\[\frac{1 + \sin(\theta) }{\cos(\theta)} = p\]

then solved for sin(theta)

Answer 12

1+sin theta=p cos theta

Answer 13

yep... then you can find sin

Answer 14

sin theta=p cos theta-1

Answer 15

well that makes sense to me looking at the question you posted...

I'm not sure of the circumstances of the question... and just went with the obvious

using a little knowledge of trig..

Answer 16

nope. i need answer in p form without trigonometric function in answer