Question

HELP!

Answer 1

?

Answer 2

cos theta.

Answer 3

open up the formulas of sin(30+thata) and cos(30+theta) as

then sin theta/2 will be cancelled and yyou will get cos thets/2+cos theta/2=cos theta

Answer 4

you get it or not..?

Answer 5

I got it! What about this one?

Answer 6

SEE :

LHS = sin(θ+30°) + cos(θ + 60°)= (sin θ . cos 30° + cos θ . sin 30°) + (cos θ cos 60° − sin θ sin 60°)=3√2 sin θ + cos θ2 + cos θ2 − 3√2 sin θ=cos θ2 + cos θ2=cos θ = RHS ....
....................Hope it helps...........

Answer 7

@princeharryyy @OOOPS @superhelp101 can anyone help with the second attached file?

Answer 8

ist find the values of sinx and cos x...using tanx=-4/3

as tan x= perp/base

so for right triangle use pthagoras theorem to find hypatenneous as

hypt^2=base^2+perp^

the use this

sin x=perp/hypt

cos x= base/hypt

then just plug values and get result..

Answer 9

do you know the result?

Answer 10

@zaibali.qasmi

Answer 11

yes...just a momen.

Answer 12

wait few minutes doing some imp stuff

Answer 13

will message u the soln try others till then

Answer 14

it should be option B...

Answer 15

sin(30+theta) is equal to cos(90-(30+theta));
so now the equation becomes cos(60-theta) + cos(60+theta);
=> 2cos((60-theta + 60 + theta)/2)cos((60-theta - 60 - theta)/2);
to get cos(theta) as your answer @Katieholmes

Answer 16

perfect!