Question

How to simplify y=ce^(-ln(x)-x)?

Answer 1

@dan815 @Abhisar @ganeshie8

Answer 2

\[\large \begin{align} \\ y &= ce^{-\ln(x) - x} \end{align}\]

Answer 3

\[\large \begin{align} \\ &= ce^{-(\ln(x) + x)} \end{align}\]

Answer 4

\[\large \begin{align} \\ &= \dfrac{c}{e^{(\ln(x) + x)} }\end{align}\]

Answer 5

\[\large \begin{align} \\ &= \dfrac{c}{e^{\ln(x)}*e^{ x} }\end{align}\]

Answer 6

\[\large \begin{align} \\ &= \dfrac{c}{x*e^{ x} }\end{align}\]

Answer 7

i gues thats it ^

Answer 8

Okay, when it says find the general solution of y'+ay=0, for example, how do I find the answer on Ti-89 calculator? Like what's the input?

Answer 9

sorry not sure... i haven't used Ti-89 for like 10 years
@UnkleRhaukus

Answer 10

Thanks for the help.