Question

Find \(\large \left(\frac{2}{6}\right)^2 \cdot \left(\frac{9}{27}\right)^3\).

Answer 1

\(\huge \left(\frac{2}{6}\right)^2 \cdot \left(\frac{9}{27}\right)^3\)

Answer 2

yep

Answer 3

look at the second fraction,
9 goes in 27 right ?

Answer 4

yeah

Answer 5

how many times ?

Answer 6

3

Answer 7

\(\huge \left(\frac{2}{6}\right)^2 \cdot \left(\frac{9}{9*3}\right)^3\)


\(\huge \left(\frac{2}{6}\right)^2 \cdot \left(\frac{1}{3}\right)^3\)

Answer 8

Oh look at first fraction,
2 also goes in 6, right ?

Answer 9

yeah

Answer 10

\(\huge \left(\frac{2}{6}\right)^2 \cdot \left(\frac{9}{9*3}\right)^3\)


\(\huge \left(\frac{1}{3}\right)^2 \cdot \left(\frac{1}{3}\right)^3\)

Answer 11

that simplifies to :



\(\huge \frac{1}{3^2 \bullet 3^3}\)

Answer 12

further simplifies to :

\(\huge \frac{1}{3^{2+3} }\)