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OpenStudy (ikram002p):
like how many digits the answer will be ?
or what is first digit ?
OpenStudy (mathmath333):
hundred,ten,unit..........units digit is needed (one digit)
OpenStudy (ikram002p):
what lol ?
OpenStudy (anonymous):
Dude man there's like 285 decimal places
OpenStudy (ikram002p):
haha bat :P
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OpenStudy (ikram002p):
ok just determine which digit you want to find hehe
:P
OpenStudy (anonymous):
10^284 idk what it's called
OpenStudy (mathmath333):
lets assume ans will be .....88999812
here units digit is 2
OpenStudy (dls):
115359438714681346382145850061896213461923232053969372763963859870671636459648757732966007126670442160564203941945826884169658186442957982512790889307915775164917252041299013231302130473445843179328581228029719622838038897741862629063384847601854612992902492312967602215395516924035072
Answer is 2.
:"D
OpenStudy (ikram002p):
ohhh lol i asked u that :o
so u wanna first digit :P
ok
(52^97)*(43^72) mod 10
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OpenStudy (anonymous):
xD
OpenStudy (ikram002p):
yeah this is bat :P
can u solve it ?
OpenStudy (ikram002p):
DLS :P
OpenStudy (ikram002p):
brb ill solve it using mod thingy
OpenStudy (anonymous):
Tis 2
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ganeshie8 (ganeshie8):
you need to take mod 10 right ?
OpenStudy (mathmath333):
yes
ganeshie8 (ganeshie8):
take it
ganeshie8 (ganeshie8):
you have done several problems like this before, right ?
ganeshie8 (ganeshie8):
(52^97)*(43^72) mod 10
reduce
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OpenStudy (mathmath333):
yes but it is still confusing
OpenStudy (mathmath333):
2^97 and 3^72
ganeshie8 (ganeshie8):
thats a good start :)
ganeshie8 (ganeshie8):
(52^97)*(43^72) mod 10
(2^97)*(3^72) mod 10
ganeshie8 (ganeshie8):
whats next
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OpenStudy (mathmath333):
(2^19)(4)*(7^24)
OpenStudy (ikram002p):
oh the question been taken xD
OpenStudy (mathmath333):
(2^3)(2^6)*(-1)
ganeshie8 (ganeshie8):
step by step. see if below makes sense :
(52^97)*(43^72) mod 10
(2^97)*(3^72) mod 10
(2^97)*(3^2)^36 mod 10
(2^97)*(-1)^36 mod 10
(2^97) mod 10
OpenStudy (anonymous):
Ganeshie for OS presidency xD
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OpenStudy (ikram002p):
-.-
OpenStudy (anonymous):
<3
OpenStudy (ikram002p):
i only went for 2 mnts xD
and come back found it taken lol
OpenStudy (ikram002p):
moshera mo monsheran meh damoh
OpenStudy (mathmath333):
u ingored (-1) because its even power?
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ganeshie8 (ganeshie8):
(-1) was not ignored.
(-1)^36 = +1
OpenStudy (mathmath333):
ohh
ganeshie8 (ganeshie8):
Oh sorry i skipped a step, see if below looks okay :
(52^97)*(43^72) mod 10
(2^97)*(3^72) mod 10
(2^97)*(3^2)^36 mod 10
(2^97)*(-1)^36 mod 10
`(2^97)*(+1) mod 10`
(2^97)mod 10
ganeshie8 (ganeshie8):
@ikram002p stop cussing >.<
show him how to reduce (2^97)mod 10
OpenStudy (ikram002p):
u started -.-
u show him
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ganeshie8 (ganeshie8):
@mathmath333 happy with the reduction so far ?
OpenStudy (mathmath333):
yes its coming 2
ganeshie8 (ganeshie8):
looks good !
OpenStudy (mathmath333):
yes
OpenStudy (ikram002p):
as a reduce in case u wanna something less than 10
(2^97)mod 10=(2^97)mod 5 ( since 10=2*5) and (2^97 =0 mod 2)
so work on this
(2^97)mod 5
just for information :P
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