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Mathematics 18 Online
OpenStudy (anonymous):

60% of the school population voted Alan as the president of student council. A random sample of 10 students was taken from the school population. Calculate the probability of a) 3 students voted Alan as the president. Ans: b) less than 3 students voted Alan as the president. Ans: c) at least 3 students voted Alan as the president. Ans:

OpenStudy (amriju):

a)10C3*.6

OpenStudy (amriju):

b) summation( i= 0,1,2) 10Ci*.6

OpenStudy (amriju):

c)1-b

OpenStudy (anonymous):

so for (b) is it 0.01 after rounding off to 2 d.p?

OpenStudy (anonymous):

I'm not sure of the answers, sorry :(

OpenStudy (amriju):

pellet..it should be 0.6^3 for a..0.6^i for b..

OpenStudy (anonymous):

oh for a is 0.216, how about part b? :)

OpenStudy (amriju):

part b is like less than 3 students..so you can say it consists of three cases...0 students voted, 1 student voted or 2 students voted..you know how to determine the prob of each one of them...and you need to add all of them...

OpenStudy (anonymous):

can you list down the answers so I can check with mine?

OpenStudy (amriju):

ok..wait..

OpenStudy (anonymous):

I got these: (a) 0.04 (2d.p) (b) 0.216 (0.22 2d.p) (c) 0.784 (0.78 2d.p)

OpenStudy (amriju):

and a) is not 0.216..i meant .6^3*10C3...not .6*10^3 as I posted earlier..i meant that

OpenStudy (anonymous):

i need all the final answers thanks :)

OpenStudy (amriju):

k..

OpenStudy (amriju):

a) .04

OpenStudy (anonymous):

yea got the same as yours for part a

OpenStudy (amriju):

b is too big... :( :(

OpenStudy (amriju):

are you doing probabilty using binomial theorem?

OpenStudy (anonymous):

binomial distribution?

OpenStudy (anonymous):

:<

OpenStudy (amriju):

yo:)

OpenStudy (amriju):

whats that smiley?

OpenStudy (anonymous):

sad one...

OpenStudy (anonymous):

How about I ask another question?

OpenStudy (amriju):

yeah...no problem...but learn binomial distribution and you'll be able to solve problems like this

OpenStudy (anonymous):

okay I message you or...?

OpenStudy (amriju):

no probs..

OpenStudy (anonymous):

Sent you :)

OpenStudy (amriju):

yup..got it..

OpenStudy (amriju):

its not clear if he attempted all the questions..assuming he did..then..a) 15C2*(.2)^2(.8)^13

OpenStudy (amriju):

b) summation that he scored 0, 1, 2 ,3 or 4 marks..use the same process as in part a..

OpenStudy (anonymous):

oh thanks got both the questions already. help me with the last I posted :)

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