60% of the school population voted Alan as the president of student council. A random sample of 10 students was taken from the school population. Calculate the probability of a) 3 students voted Alan as the president. Ans: b) less than 3 students voted Alan as the president. Ans: c) at least 3 students voted Alan as the president. Ans:
a)10C3*.6
b) summation( i= 0,1,2) 10Ci*.6
c)1-b
so for (b) is it 0.01 after rounding off to 2 d.p?
I'm not sure of the answers, sorry :(
pellet..it should be 0.6^3 for a..0.6^i for b..
oh for a is 0.216, how about part b? :)
part b is like less than 3 students..so you can say it consists of three cases...0 students voted, 1 student voted or 2 students voted..you know how to determine the prob of each one of them...and you need to add all of them...
can you list down the answers so I can check with mine?
ok..wait..
I got these: (a) 0.04 (2d.p) (b) 0.216 (0.22 2d.p) (c) 0.784 (0.78 2d.p)
and a) is not 0.216..i meant .6^3*10C3...not .6*10^3 as I posted earlier..i meant that
i need all the final answers thanks :)
k..
a) .04
yea got the same as yours for part a
b is too big... :( :(
are you doing probabilty using binomial theorem?
binomial distribution?
:<
yo:)
whats that smiley?
sad one...
How about I ask another question?
yeah...no problem...but learn binomial distribution and you'll be able to solve problems like this
okay I message you or...?
no probs..
Sent you :)
yup..got it..
its not clear if he attempted all the questions..assuming he did..then..a) 15C2*(.2)^2(.8)^13
b) summation that he scored 0, 1, 2 ,3 or 4 marks..use the same process as in part a..
oh thanks got both the questions already. help me with the last I posted :)
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