Question

A ball is released from the top of the tower at a height h metre .it takes t seconds to reach the ground. What is the position of the ball t/3 second

Answer 1

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Answer 2

For the first case
\(\sf \large h=\frac{1}{2}gt^2\\ \Rightarrow t^2=\huge\frac{2h}{g}\)

Answer 3

Now in the second case,
\(\large \sf S=\frac{1}{2}g\frac{t^2}{9}\\ \Rightarrow\huge \frac{18S}{g}=t^2\)

Answer 4

comparing two equations we get that,
S=\(\sf \huge\frac{h}{9}\)

Answer 5

got it ?

Answer 6

?????

Answer 7

Ur 2nd equation plz explain

Answer 8

Take s=ut+1/2at^2....
Put the value of u as 0, a as g and t as t/3

Answer 9

Thank you

Answer 10

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