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what is cosine, do you recall?
Use SOH CAH TOA (read it like it is written) Sin(Θ) = Opposite/Hypothesis Cos(Θ) = Adjacent/Hypothesis Tan(Θ) = Opposite/Hypothesis
use the Pythagorean thm to find out h
then you have your answer
These terms can be rewritten to, Θ = arcsin(Opposite/Hypothesis) Θ = arccos(Adjacent/Hypothesis) Θ = arctan(Opposite/Hypothesis)
we don't need those
One way to do this problem: Find the angle Θ Then just take cos(theta)
5²+12²=13, but it looks like this doesn't apply here, because the point is diagonally from the triangle, I would understand if it was (-13,5)
or if it was (5,-13)
maybe, it IS 13, and not 12 ?
-:(
Well you can still solve it, but beware that 12 is a hypotenuse, not one of the legs.
Or not, I am wrong
(12,-5) Yes, I am wrong \(\Huge\color{blue}{ \bf | }\) \(\Huge\color{blue}{ \bf | }\) \(\Huge\color{blue}{ \bf | }\) \(\Huge\color{blue}{ \bf ^ \text{__ __ __} }\) \(\Huge\color{blue}{ \bf ✛ }\)\(\Huge\color{blue}{ \bf ^ \text{__ __ __} }\) \(\Huge\color{blue}{ \bf | }\) \(\Huge\color{blue}{ \bf | }\) \(\Huge\color{blue}{ \bf • }\)(12,-5) \(\Huge\color{blue}{ \bf | }\)
GOod I am sorry, my brain wasn't working, the hyp IS 13.
Follow their direction, sorry for confusing you again
omg ?
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cosine (theta) = adj/hy cos(theta)=12/13
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