The distance traveled, in meters, of a coin dropped from a tall building is modeled by the equation d(t) = 4.9t2 where d equals the distance traveled at time t seconds and t equals the time in seconds. What does the average rate of change of d(t) from t = 3 to t = 6 represent? The coin travels an average distance of 44.1 meters from 3 seconds to 6 seconds. The coin falls down with an average speed of 14.7 meters per second from 3 seconds to 6 seconds. The coin falls down with an average speed of 44.1 meters per second from 3 seconds to 6 seconds.
The coin travels an average distance of 14.7 meters from 3 seconds to 6 seconds.
@phi @hero
average rate of change of d(t) ? from t = 3 to t = 6 change in distance over change in time does that sound familiar? distance/time people call that speed. so you should expect the answer to be related to speed
to figure out the average speed you need to use the formula to find how far the coin fell between t=3 and t=6 then divide by 3 seconds (change in time is 6-3 = 3 seconds) to get the speed
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