Question

The surface area of this pyramid is one hundred eighty-nine square centimeters. The area of the square base is forty-nine square centimeters. What is the area of one triangular face of the lateral surface? Show the steps of your solution and explain your work.

Answer 1

Here's the formula 1/3 × [Base Area] × Height


http://www.mathsisfun.com/geometry/pyramids.html

Answer 2

35

Answer 3

Please explain how you got that

Answer 4

Assuming the square base is included as part of the surface area, the total surface area is
(total area) = (base area) + 4*(triangular face area)
189 cm^2 = 49 cm^2 + 4*(triangular face area)
140 cm^2 = 4*(triangular face area)
140/4 cm^2 = (triangular face area)
35 cm^2 = (triangular face area)