The expression (secx+tanx)^2 is the same as
A. sec^2 x + 2cscx + tan^2 x
B. 1 + 2cscx
C. sec^2 x + tan^2 x
D. 1 + 2tan^2 x + 2secx tanx

Thanks!

Question

The expression (secx+tanx)^2 is the same as
A. sec^2 x + 2cscx + tan^2 x
B. 1 + 2cscx
C. sec^2 x + tan^2 x
D. 1 + 2tan^2 x + 2secx tanx

Thanks!

solomonzelman · Answer

re-writing in terms of sines and cosines would be helpful.

anonymous · Answer

I suggest choosing an angle for x and plugging it into the the expressing and then use the same value for x and plug it into the options provided. The one that will give you the same value is the same expression.

anonymous · Answer

The other way is manipulation of trigonometric identities.

anonymous · Answer

So like I'll plug in x=2.
Then solve 1+2csc(2) = (sec(2)+tan(2))^2

anonymous · Answer

x is an angle in this case.

anonymous · Answer

Wouldn't theta, rather than x, typically be an angle? Are you implying x = 2 degrees?

anonymous · Answer

No I mean that x should be an angle from 0 to 90. Other angles would work but these angles are easier to deal with.

anonymous · Answer

Okay so solving sec(2 degrees)+tan(2 degrees) gives me about 1.04, correct?