When looking at a rational function, Jamal and Angie have two different thoughts. Jamal says that the function is defined at x = −3, x = −4, and x = 6. Angie says that the function is undefined at those x values. Describe a situation where Jamal is correct, and describe a situation where Angie is correct. Is it possible for a situation to exist where they are both correct? Justify your reasoning.

Question

anonymous · Answer

@agreene

zzr0ck3r · Answer

so we get undefined if we divide by 0

so what could we do, so that when we plug in -3,-4,or 6, it forces us to divide by 0?

$f(x) = \frac{1}{(x+3)(x+4)(x-6)}$ would be one such function

zzr0ck3r · Answer

$f(x) = x$ is defined for all real numbers

and one would be hard pressed (find it impossible) to find a function that is defined and undefined for a certain x

anonymous · Answer

@zzr0ck3r thanks :D

zzr0ck3r · Answer

if you have any question just ask

anonymous · Answer

@zzr0ck3r can you help me with one more?

anonymous · Answer

Kelly tells you that when variables are in the denominator, the equation becomes unsolvable. "There is a value for x that makes the denominator zero, and you can't divide by zero," Kelly explains. Using complete sentences, demonstrate to Kelly how the equation is still solvable.

anonymous · Answer

@precal

precal · Answer

what is this? story telling math?