Question

The total number of ways, in which letters of the word ‘ACCOST’ can be arranged, so that the two Cs never come together, is

Answer 1

cc -consider as one unit,so 5! ways

Answer 2

6!-5! ways=602 ways
take cc as a grp then permute it .you will get the total number of words with cc together
then minus it from the max number of ways you can form word
you get 602

Answer 3

@ganeshie8 can you help me please i tagged you

Answer 4

then the two cc should not be together so .how to get cc seperated

Answer 5

5!*2!

Answer 6

@DELKATTY69 's approach is correct, but the answer is slightly wrong

Answer 7

6!-5!*2!

Answer 8

it may appear wrong but i believe its correct

Answer 9

‘ACCOST’

i think total number of permutations = \(\large \dfrac{6!}{2!}\)

Answer 10

please concentrate on the second part not the cc together part

Answer 11

6!/2! cuz c repeated twice

Answer 12

permutations with CC together = \(\large 5!\)

so the required permutations with CC never together = \(\large \dfrac{6!}{2!} - 5!\)

Answer 13

see if that looks okay @DELKATTY69 :)

Answer 14

240

Answer 15

but bit confusing

Answer 16

as i told earlier we have c two times so we are dividing

Answer 17

well forgot 6C2 part sorry

Answer 18

`numbers with CC together` + `numbers with CC not together` = `total numbers`

Answer 19

^^