limit of f of x as x approaches 5 where f of x equals 5 minus x when x is less than 5, 8 when x equals 5, and x plus 3 when x is greater than 5
Find the indicated limit, if it exists.
if you need to see the choices it's: 0 8 3 The limit does not exist.
I got 0
Is this info right? \[f(x)=\begin{cases}5-x&\text{for }x<5\\ 8&\text{for }x=5\\ x+3&\text{for }x>5\end{cases}\] Find \[\large\lim_{x\to5}f(x)\]
yes
To see if the limit exists at all, you have to check the limits from both sides. If you have \[\large\lim_{x\to5^-}f(x)=\lim_{x\to5^+}f(x)\] then the limit exists, and \[\large\lim_{x\to5}f(x)\] is the actual limit. To check the one-sided limits, you have to use the appropriate functions. For \(x\to5^-\), you use the function defined for values of \(x\) to the left of 5, or \(x<5\). For \(x\to5^+\), you use the function defined for \(x>5\): \[\large\lim_{x\to5^-}f(x)=\lim_{x\to5^-}(5-x)\\ \large\lim_{x\to5^+}f(x)=\lim_{x\to5^+}(x+3)\]
THIS MAKES SO MUCH MORE SENSE
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