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Mathematics 15 Online
OpenStudy (anonymous):

limit of f of x as x approaches 5 where f of x equals 5 minus x when x is less than 5, 8 when x equals 5, and x plus 3 when x is greater than 5

OpenStudy (anonymous):

Find the indicated limit, if it exists.

OpenStudy (anonymous):

if you need to see the choices it's: 0 8 3 The limit does not exist.

OpenStudy (anonymous):

I got 0

OpenStudy (anonymous):

Is this info right? \[f(x)=\begin{cases}5-x&\text{for }x<5\\ 8&\text{for }x=5\\ x+3&\text{for }x>5\end{cases}\] Find \[\large\lim_{x\to5}f(x)\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

To see if the limit exists at all, you have to check the limits from both sides. If you have \[\large\lim_{x\to5^-}f(x)=\lim_{x\to5^+}f(x)\] then the limit exists, and \[\large\lim_{x\to5}f(x)\] is the actual limit. To check the one-sided limits, you have to use the appropriate functions. For \(x\to5^-\), you use the function defined for values of \(x\) to the left of 5, or \(x<5\). For \(x\to5^+\), you use the function defined for \(x>5\): \[\large\lim_{x\to5^-}f(x)=\lim_{x\to5^-}(5-x)\\ \large\lim_{x\to5^+}f(x)=\lim_{x\to5^+}(x+3)\]

OpenStudy (anonymous):

THIS MAKES SO MUCH MORE SENSE

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