Question

Write the given expression as an algebraic expression tan(2 sin^−1 x) in x

Answer 1

look up the double angle formula for tangent
i forget what it is but that is what you need

Answer 2

tan(2arcsin(x)) To make it easier to see for myself.

Answer 3

maybe
\[\tan(2x)=\frac{2\tan(x)}{1-\tan^2(x)}\]? something like that?

Answer 4

Yeah thats it.

Answer 5

then \[\frac{2\tan(\arcsin(x)}{1-\tan^2(\arcsin(x)}\] is a start

Answer 6

all you need is \(\tan(\arcsin(x))\) to finish

Answer 7

Let y = arcsin(x)
Then sin(y) = x, and tan(arc sin x) = tan(y)

Answer 8

arcsin(sin(y)) = y

Answer 9

\[= \frac{ 2\tan(y) }{ 1-\tan ^{2}(y) }\]

Answer 10

this is what i get, is rite? tan(y) =[2x((√1-x^2)+x)]/(1-2x^2)

Answer 11

I got \[\frac{ x }{ \sqrt{1-x ^{2}} }\]

Answer 12

I've put your answer into my online assignment and it stated to be incorrect?

Answer 13

Oh I've got it, it's [2x \sqrt{1-x^2}/(1-2x^2)\]

Answer 14

\[(2x \sqrt{1-x^2})/(1-2x^2)\]