Question

@iambatman

Answer 1

Calculate the potential difference between x and y

Answer 2

I haven't done one of these in ages haha

Answer 3

any idea...how to approach ?

Answer 4

Branch current method?

Answer 5

What's that ?

Answer 6

u mean kirchhoff's 1st rule ?

Answer 7

Actually mesh current method would work I suppose, it uses Kirchhoff's voltage laws, and ohm's law to find the unknown currents in certain networks.

Answer 8

I'm just trying to remember because it's been so long since I've dealt with such

Answer 9

ohh..

Answer 10

Same is with me...i read all these stuffs back in A level

Answer 11

Yeah, it's been sometime I think I would have to think about this, I was never a fan of bridge circuits.

Answer 12

yeah me too...i was and am more into mechanics

Answer 13

Yeah haha

Answer 14

Hey actually check this out: http://www.allaboutcircuits.com/vol_1/chpt_10/3.html

Answer 15

actually i read these stuffs....i am not able to think how to determine potential difference between x and y if they are not connected. At first i thought it would be 0 but the answer is 1

Answer 16

Mhm what have you done so far? Maybe @ParthKohli would be better to help you with this one, I'd have to go over my work haha and I'm too lazy for that right now.

Answer 17

yeah i can understand...

Answer 18

Sorry AB, I'll probably get back to you later on this one, if you haven't figured it out by then. I'll probably go look for my notes later tonight. Sorry man.

Answer 19

That's allryt man...

Answer 20

\(\color{blue}{\text{Originally Posted by}}\) @iambatman
Sorry AB, I'll probably get back to you later on this one, if you haven't figured it out by then. I'll probably go look for my notes later tonight. Sorry man.
\(\color{blue}{\text{End of Quote}}\)


This statement is enough !!
u won my heart :D

Answer 21

ohkay...till then i'll try it myself to figure it out ;)

Answer 22

Haha alright, well good luck man, electromagnetism and such is where my ignorance lies when it comes to physics. I was alright at it at the time, but never fully understood all the concepts, thanks for bringing this up though, makes me more curious and wanting to find the answer!

Answer 23

aaahhh !
Let's see who finds it first ;) [I hate electromagnetism too :( ]

Answer 24

This is my attempt...it's giving out the answer without circuit laws...IDK if it is correct !

Let us define a point A. In || combination current divides according to the resistance ratios. The given circuit can be equivalently represented as

Now \(\sf I_1=\frac{\large 5}{\large 5}\times1=1A\\ \Rightarrow I_2=2-1=1A\\ Now,~V_a-V_x=I_1\times 2Ω=1\times 2=2\\ V_a-V_y=I_2\times 3Ω=1 \times 3=3\\ V_x-V_y=V_a-V_y-(V_a-V_x)=3-2=1V\)