Mathematics
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OpenStudy (anonymous):
medals!! help with a couple math problems
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OpenStudy (anonymous):
Find the center, vertices, and foci of the ellipse with equation 5x^2 + 9y^2 = 45.
OpenStudy (anonymous):
Center would be (0,0)
OpenStudy (anonymous):
@ganeshie8
OpenStudy (anonymous):
vertices would be (0, -3), (0, -3)?
ganeshie8 (ganeshie8):
not sure yet, first rewrite in standard form :
\[\large \dfrac{x^2}{a^2} + \dfrac{y^2}{b^2}= 1\]
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ganeshie8 (ganeshie8):
to get into standard form, simply divide 45 both sides
OpenStudy (anonymous):
5x^2/45+9y^2/45 = 1
ganeshie8 (ganeshie8):
yes! simplify the fractions
OpenStudy (anonymous):
x^2/9+ x^2/5 = 1
ganeshie8 (ganeshie8):
\[\large \dfrac{x^2}{9} + \dfrac{y^2}{5}= 1\]
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ganeshie8 (ganeshie8):
since the number below x is greater than the number below y,
this is a horizontal ellipse, right ?
OpenStudy (anonymous):
yesss
ganeshie8 (ganeshie8):
|dw:1407590562333:dw|
ganeshie8 (ganeshie8):
that means vertices will be on x axis, yes ?
OpenStudy (anonymous):
yes
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ganeshie8 (ganeshie8):
|dw:1407590672172:dw|
ganeshie8 (ganeshie8):
good :)
from the equation, we have \(a = 3\)
can u write the coordinates of vertices ?
OpenStudy (anonymous):
(-3, 0), (3, 0)
ganeshie8 (ganeshie8):
Correct !
OpenStudy (anonymous):
and the foci would be(-2, 0), (2, 0) (:
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ganeshie8 (ganeshie8):
thats right ! good job !!