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Mathematics 18 Online
OpenStudy (anonymous):

medals!! help with a couple math problems

OpenStudy (anonymous):

Find the center, vertices, and foci of the ellipse with equation 5x^2 + 9y^2 = 45.

OpenStudy (anonymous):

Center would be (0,0)

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

vertices would be (0, -3), (0, -3)?

ganeshie8 (ganeshie8):

not sure yet, first rewrite in standard form : \[\large \dfrac{x^2}{a^2} + \dfrac{y^2}{b^2}= 1\]

ganeshie8 (ganeshie8):

to get into standard form, simply divide 45 both sides

OpenStudy (anonymous):

5x^2/45+9y^2/45 = 1

ganeshie8 (ganeshie8):

yes! simplify the fractions

OpenStudy (anonymous):

x^2/9+ x^2/5 = 1

ganeshie8 (ganeshie8):

\[\large \dfrac{x^2}{9} + \dfrac{y^2}{5}= 1\]

ganeshie8 (ganeshie8):

since the number below x is greater than the number below y, this is a horizontal ellipse, right ?

OpenStudy (anonymous):

yesss

ganeshie8 (ganeshie8):

|dw:1407590562333:dw|

ganeshie8 (ganeshie8):

that means vertices will be on x axis, yes ?

OpenStudy (anonymous):

yes

ganeshie8 (ganeshie8):

|dw:1407590672172:dw|

ganeshie8 (ganeshie8):

good :) from the equation, we have \(a = 3\) can u write the coordinates of vertices ?

OpenStudy (anonymous):

(-3, 0), (3, 0)

ganeshie8 (ganeshie8):

Correct !

OpenStudy (anonymous):

and the foci would be(-2, 0), (2, 0) (:

ganeshie8 (ganeshie8):

thats right ! good job !!

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