Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false.

12 + 42 + 72 + ... + (3n - 2)2 = (n(6n^2-3n-1))/2

Question

Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false.

12 + 42 + 72 + ... + (3n - 2)2 = (n(6n^2-3n-1))/2

anonymous · Answer

@midhun.madhu1987 If I do this one, can you just check my work over?

midhun.madhu1987 · Answer

yes.. sure.. i can check.. :)

anonymous · Answer

Awesome, so first I have to square the whole left side, right?

midhun.madhu1987 · Answer

prove for p(1)

midhun.madhu1987 · Answer

The statement is valid only if P(1) is TRUE

anonymous · Answer

This is what I got:

9n^2-12n+4=(n(6n^2-3n-1))/2
(9(1))^2-12(1)+4=(1((6(1))^2-3(1)-1))/2
9^2-12+4=(1(6^2)-3-1)/2
81-12+4=(36-3-1)/2
73=32/2
73=16

So I'm thinking it's false

midhun.madhu1987 · Answer

|dw:1407613759295:dw|


so p(1) is true