Question

Find the equation of the circle with center at (3, 2) and through the point (5, 4).

Answer 1

@Kainui @Nurali

Answer 2

What is the equation of a circle?
What is the radius of this circle?

Answer 3

Isn't it Pythagorean?

Answer 4

And I have no clue what the radius is

Answer 5

The radius is the distance from the center to any point on the circle. In this case, one of the points on the circle is (5,4)

I think the distance formula would work

Answer 6

Im not sure if the question is asking for the equation to solve it or if its asking for the answer through using the distance formula. Can you tell which its asking for?

Answer 7

It's asking for an equation. First, find the equation for a circle

Answer 8

I'd want to use this correct? (x – h)2 + (y – k)2 = r2

Answer 9

Yes. What is h, k?

Answer 10

It was from this

http://static.k12.com/eli/bb/348/-1/0/1_45222_24116/-1/a08d9a696b3201e80062547300d6ddc76dd91e04/media/1ea235e743c6eadc5c83f7cfefe5fb70b4c256a8/mediaasset_653134_1.gif

Answer 11

I meant what are the numbers that fit h and k lol

Answer 12

Oh sorry. 3 and 2 (h and k)

Answer 13

So now we have the following:\[\huge {(x – 3)}^2 + {(y – 2)}^2 = r^2\]

Answer 14

we want to find the radius. now recall that the distance from 5,4 to 3,2 is the radius

Answer 15

So we need to use the distance formula then?

Answer 16

Yes.

Answer 17

I got 2.82
(5-3)^2+(4-2)^2
2^2+2^2 = 8
sqr. root of 8 being 2.82

Answer 18

You can leave it as sqrt(8) because look at what happens when we plug it in\[\huge {(x – 3)}^2 + {(y – 2)}^2 = \sqrt{8}^2\]\[\huge {(x – 3)}^2 + {(y – 2)}^2 = \sqrt{8}^ \cancel 2\]\[\huge {(x – 3)}^2 + {(y – 2)}^2 =8\]

Answer 19

Oh alright so then our answer would be the last one then?

Answer 20

yup

Answer 21

Thank you for your help. I might have another one soon if you're willing to help.

Answer 22

Sure, close this question and open a new one.