Question

(I have one day to finish this or I get kicked out of my high school and home...)

An object is fired upward from the top of a 200 ft. tower at a velocity of 80 ft/sec. Find the maximum height reached by the object. Round to the nearest foot.

Answer 1

2.5ft/sec right?

Answer 2

idk..

Answer 3

yuck.

Answer 4

....

Answer 5

have you learned about conservation of energy yet?

Answer 6

...no..

Answer 7

kinetic and potential energy?

Answer 8

...idk?

Answer 9

come on, the problem is asking for a height and you're giving a speed

Answer 10

at least guess harder

Answer 11

Use this formula;\[V ^{2}=U ^{2}+ 2as\]Where V is velocity at maximum height and would be 0 as the object is at max height and now beginning to change direction
U = the initial velocity in this case 80 ft/sec
a = acceleration due to gravity and is -32 ft/sec/sec. Note the negative value.\[0=80^{2}-2*32*s\]
s = height where V is 0 or maximum height.
\[64s=6400\]\[s=6400/64 = 100ft.\]Now remember you were on a 200 ft tower, so the maximum height was 200 + 100 or 300 ft.

Answer 12

I realize the question is closed, but did not see any real effort to solve this problem.
The key is the time for the object to reach maximum height is the same as the time for it to fall back down to the top of the tower.

Answer 13

Here is a good example. http://www.schoolphysics.co.uk/age16-19/Mechanics/Kinematics/text/Projectiles_vertical_projection/index.html

Answer 14

This uses meters and the acelleration due to gravity is 9.8 m/sec/sec

Answer 15

Google is a wonderful search engine, it can help you solve your math problems. I use it a lot, as there is no way I can keep everything in this old head lol.