Question

8^(x-2)=5^x
medal/follow

Answer 1

solve for x?

Answer 2

yes

Answer 3

take the log of both sides and use some log laws

\[\log(8^{x -2}) = \log(5^x)\]

applying the log laws for powers

\[(x - 2)\log(8) = x \log(5)\]

so distributing and collecting like terms

\[x(\log(8) - \log(5)) = 2\log(8)\]

so

\[x = \frac{2\log(8)}{\log(8) - \log(5)}\]

hope it helps

Answer 4

thanks so much