Question

helpp im on a timer lol

Answer 1

same thing. ax+by=c form

Answer 2

is it c or D?

Answer 3

so its c lol

Answer 4

tick tock c: what's the timer down to?

Answer 5

can someone just give me the answer -.-

Answer 6

5 mins :(

Answer 7

oh my :O

Answer 8

help bbyyy :(

Answer 9

\[\Large\rm \frac{2}{3}x+\frac{5}{2}y=2\]So we need to multiply each side by 6, yes?

Answer 10

Because that's the lowest common factor for our denominators.

Answer 11

\[\Large\rm 6\frac{2}{3}x+6\frac{5}{2}y=6\cdot2\]

Answer 12

so its A? :3

Answer 13

You're just guessing letters over and over -_- just simmer down for a sec lol
is this the last one? can we use all 3 minutes for this one?

Answer 14

i multiplied 2/3 * 6 and got 4 so i choose b -.-

Answer 15

and no theres 2 more :(

Answer 16

If you write 6 as 3times2,
\[\Large\rm (3\cdot2)\frac{2}{3}x+(3\cdot2)\frac{5}{2}y=12\]You can see that the first term shares a 3 in front and in the denominator.\[\Large\rm (\cancel{3}\cdot2)\frac{2}{\cancel{3}}x+(3\cdot2)\frac{5}{2}y=12\]Giving us:\[\Large\rm 4x+(3\cdot2)\frac{5}{2}y=12\]You can do similar with the other term.

Answer 17

Oh my bad :c

Answer 18

so its b ? a ? c? d ahahaha help omfg 1 min :(

Answer 19

Our first and last term are correct.
See how it matches up with option A so far? c:

If we finished up with the middle term, we would see that's our option.

Answer 20

C? ;)

Answer 21

You didn't leave us enough time dude >.<
I'm pretty sure it's A unless I made a boo boo.

Answer 22

so is it a or c lol help please so i can submit!!

Answer 23

A

Answer 24

Oh no the clock is tickin! :O

Answer 25

yay thanks ily omfg can you help me with 1 more? :)

Answer 26

@zepdrix

Answer 27

maybe -_-

Answer 28

<3

Answer 29

are you FLVS or something?

Answer 30

Whats that o: lol

Answer 31

Florida Virtual Schools :d nevermind.

Answer 32

I googled it but no im not lol-.- i failed 9th grade math and they gave me a week to finish alg 1 and 2 so i can graduate to college :D

Answer 33

oo neato :o

Answer 34

\[\Large\rm 12=2x+4y\]Standard form looks like this:
\(\Large\rm Ax+By=C\)
which is the same as
\(\Large\rm C=Ax+By\)

Where \(\Large\rm A\), \(\Large\rm B\) and \(\Large\rm C\) are integers.
Usually C is supposed to be positive I think.....

Answer 35

So, based on that information, what do you think? :d

Answer 36

b

Answer 37

\[\Large\rm 12=\color{#CC0033}{2}x+\color{#3366CF}{4}y\]\[\Large\rm 12=\color{#CC0033}{A}x+\color{#3366CF}{B}y\]

So this is showing us that,
\(\Large\rm \color{#CC0033}{A=2}, \qquad\qquad \color{#3366CF}{B=4}\)

`The requirement that A and B are NOT both zero is not satisfied`.

Answer 38

Hmmm that doesn't sound right.
That IS satisfied, correct?

Answer 39

yeah c:

Answer 40

So try again >:U

Answer 41

its a or b -.-

Answer 42

Woops I made a small boo boo in my explanation.
The \(\Large\rm A\) value should be positive for it to be in standard form, not necessarily \(\Large\rm C\).

Answer 43

It's actually D.
I'm not quite sure why you don't see it :c

Answer 44

omg sorry i was reading it wrong :(

Answer 45

i get it now omfg thanks <3

Answer 46

We have `some number of x's` plus `some number of y's` = `a number` right? :o
standard

Answer 47

k :3

Answer 48

help me with 1 more ;) ?

Answer 49

fine <.<

Answer 50

ok this is the last one i promise :3

Answer 51

Do you know how to plot points? 0_o

Answer 52

yes -.-